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CIE 9231 2024 June Paper 22 Q7

A Level / CIE / FP2

CIE 9231 2024 June Paper 22 Paper · Question 7

题目

Problem

(a) Use the substitution u=1+x2u=1+x^2 to find

x1+x2dx.\int\frac{x}{\sqrt{1+x^2}}\,\mathrm{d}x.
[2]

(b) Find the solution of the differential equation

xdydxy=x2sinh1x,x\frac{\mathrm{d}y}{\mathrm{d}x}-y=x^2\sinh^{-1}x,

given that y=1y=1 when x=1x=1. Give your answer in the form y=f(x)y=f(x).

[10]
题目中文翻译

(a) 使用代换 u=1+x2u=1+x^2

x1+x2dx\int\frac{x}{\sqrt{1+x^2}}\,\mathrm{d}x

(b) 求微分方程

xdydxy=x2sinh1xx\frac{\mathrm{d}y}{\mathrm{d}x}-y=x^2\sinh^{-1}x

的解,已知当 x=1x=1y=1y=1。将答案写成 y=f(x)y=f(x) 的形式。

解答