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CIE 9231 2025 June Paper 23 Q6

A Level / CIE / FP2

CIE 9231 2025 June Paper 23 Paper · Question 6

题目

Problem

The diagram shows the curve with equation y=1x2+1y = \frac{1}{x^2 + 1} for 0x10 \le x \le 1, together with a set of nn rectangles of width 1n\frac{1}{n}.

(a) By considering the sum of the areas of these rectangles, show that

r=1nnn2+r2<14π.\sum_{r = 1}^{n} \frac{n}{n^2 + r^2} < \frac{1}{4}\pi.
[5]

(b) Use a similar method to find a lower bound for r=1nnn2+r2\sum_{r = 1}^{n} \frac{n}{n^2 + r^2}. Give your answer in terms of nn and π\pi.

[4]

(c) Deduce the exact value of limnr=1nnn2+r2\lim_{n \to \infty}\sum_{r = 1}^{n} \frac{n}{n^2 + r^2}.

[1]
题目中文翻译

图中显示曲线 y=1x2+1y = \frac{1}{x^2 + 1},其中 0x10 \le x \le 1,以及一组宽度为 1n\frac{1}{n}nn 个矩形。

(a) 通过考虑这些矩形面积之和,证明

r=1nnn2+r2<14π.\sum_{r = 1}^{n} \frac{n}{n^2 + r^2} < \frac{1}{4}\pi.

(b) 使用类似方法,求 r=1nnn2+r2\sum_{r = 1}^{n} \frac{n}{n^2 + r^2} 的一个下界。答案需用 nnπ\pi 表示。

(c) 推出 limnr=1nnn2+r2\lim_{n \to \infty}\sum_{r = 1}^{n} \frac{n}{n^2 + r^2} 的精确值。

解答