Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9231 2025 June Paper 24 Q1

A Level / CIE / FP2

CIE 9231 2025 June Paper 24 Paper · Question 1

题目

Problem

(a) Find the values of kk for which the system of equations

x+2y+3z=1,kx+5y+6z=2,7x+2ky+9z=3\begin{aligned} x + 2y + 3z &= 1,\\ kx + 5y + 6z &= 2,\\ 7x + 2ky + 9z &= 3 \end{aligned}

does not have a unique solution.

[3]

(b) Given that k=1k = 1, show that the system of equations in part (a) is consistent. Interpret this situation geometrically.

[3]
题目中文翻译

(a) 求使下列方程组没有唯一解的 kk 值:

x+2y+3z=1,kx+5y+6z=2,7x+2ky+9z=3\begin{aligned} x + 2y + 3z &= 1,\\ kx + 5y + 6z &= 2,\\ 7x + 2ky + 9z &= 3 \end{aligned}

(b) 已知 k=1k = 1,证明第 (a) 部分的方程组相容,并从几何角度解释这一情形。

解答