Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9231 2025 June Paper 24 Q3

A Level / CIE / FP2

CIE 9231 2025 June Paper 24 Paper · Question 3

题目

Problem

Find the particular solution of the differential equation

d2ydx2+4dydx+5y=13e3x\frac{\mathrm{d}^2y}{\mathrm{d}x^2} + 4\frac{\mathrm{d}y}{\mathrm{d}x} + 5y = 13e^{3x}

given that y=1y = 1 and dydx=0\frac{\mathrm{d}y}{\mathrm{d}x} = 0 when x=0x = 0.

[10]
题目中文翻译

求微分方程

d2ydx2+4dydx+5y=13e3x\frac{\mathrm{d}^2y}{\mathrm{d}x^2} + 4\frac{\mathrm{d}y}{\mathrm{d}x} + 5y = 13e^{3x}

的特解,已知当 x=0x = 0 时,y=1y = 1dydx=0\frac{\mathrm{d}y}{\mathrm{d}x} = 0

解答