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CIE 9231 2023 November Paper 22 Q6

A Level / CIE / FP2

CIE 9231 2023 Nov Paper 22 Paper · Question 6

题目

Problem

The matrix PP is given by

P=(111021001).P=\begin{pmatrix} 1&-1&1\\ 0&2&1\\ 0&0&-1 \end{pmatrix}.

(a) State the eigenvalues of PP.

[1]

(b) Use the characteristic equation of PP to find P1P^{-1}.

[4]

The 3×33\times3 matrix AA has distinct non-zero eigenvalues aa, 12\frac{1}{2}, 22 with corresponding eigenvectors

(100),(120),(111)\begin{pmatrix}1\\0\\0\end{pmatrix},\qquad \begin{pmatrix}-1\\2\\0\end{pmatrix},\qquad \begin{pmatrix}1\\1\\-1\end{pmatrix}

respectively.

(c) Find A1A^{-1} in terms of aa.

[5]
题目中文翻译

给定矩阵 PP

P=(111021001)P=\begin{pmatrix} 1&-1&1\\ 0&2&1\\ 0&0&-1 \end{pmatrix}

(a) 写出 PP 的特征值。

(b) 利用 PP 的特征方程求 P1P^{-1}

三阶矩阵 AA 有互不相同且非零的特征值 aa12\frac{1}{2}22,其对应的特征向量依次为

(100),(120),(111)\begin{pmatrix}1\\0\\0\end{pmatrix},\qquad \begin{pmatrix}-1\\2\\0\end{pmatrix},\qquad \begin{pmatrix}1\\1\\-1\end{pmatrix}

(c) 求用 aa 表示的 A1A^{-1}

解答