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CIE 9231 2024 November Paper 21 Q4

A Level / CIE / FP2

CIE 9231 2024 Nov Paper 21 Paper · Question 4

题目

Problem

The matrix AA is given by

A=(111802016113).A = \begin{pmatrix} -11 & 1 & 8\\ 0 & -2 & 0\\ -16 & 1 & 13 \end{pmatrix}.

(a) Show that

(111)\begin{pmatrix}1\\1\\1\end{pmatrix}

is an eigenvector of AA and state the corresponding eigenvalue.

[2]

(b) Show that the characteristic equation of AA is

λ319λ30=0\lambda^3 - 19\lambda - 30 = 0

and hence find the other eigenvalues of $A.

[3]

(c) Use the characteristic equation of AA to find A1A^{-1}.

[4]
题目中文翻译

矩阵 AA 给出为

A=(111802016113)A = \begin{pmatrix} -11 & 1 & 8\\ 0 & -2 & 0\\ -16 & 1 & 13 \end{pmatrix}

(a) 证明

(111)\begin{pmatrix}1\\1\\1\end{pmatrix}

AA 的一个特征向量,并写出相应的特征值。

(b) 证明 AA 的特征方程为

λ319λ30=0\lambda^3 - 19\lambda - 30 = 0

并据此求出 AA 的其他特征值。

(c) 利用 AA 的特征方程求 A1A^{-1}

解答