题目 Problem Find the particular solution of the differential equation 3d2ydx2+2dydx+y=x2,3\frac{\mathrm{d}^2y}{\mathrm{d}x^2} + 2\frac{\mathrm{d}y}{\mathrm{d}x} + y = x^2,3dx2d2y+2dxdy+y=x2, given that, when x=0x = 0x=0, y=dydx=0y = \frac{\mathrm{d}y}{\mathrm{d}x} = 0y=dxdy=0. [10] 题目中文翻译 求微分方程 3d2ydx2+2dydx+y=x23\frac{\mathrm{d}^2y}{\mathrm{d}x^2} + 2\frac{\mathrm{d}y}{\mathrm{d}x} + y = x^23dx2d2y+2dxdy+y=x2 的特解，已知当 x=0x = 0x=0 时，y=dydx=0y = \frac{\mathrm{d}y}{\mathrm{d}x} = 0y=dxdy=0。 解答
