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CIE 9231 2025 Nov Paper 21 Q4

A Level / CIE / FP2

CIE 9231 2025 Nov Paper 21 Paper · Question 4

题目

Problem

Find the particular solution of the differential equation

5d2ydx2+2dydx+y=x2+5x+3,5\frac{\mathrm{d}^2y}{\mathrm{d}x^2} + 2\frac{\mathrm{d}y}{\mathrm{d}x} + y = x^2 + 5x + 3,

given that, when x=0x = 0, y=dydx=0y = \frac{\mathrm{d}y}{\mathrm{d}x} = 0.

[10]
题目中文翻译

求微分方程

5d2ydx2+2dydx+y=x2+5x+35\frac{\mathrm{d}^2y}{\mathrm{d}x^2} + 2\frac{\mathrm{d}y}{\mathrm{d}x} + y = x^2 + 5x + 3

的特解,已知当 x=0x = 0 时,y=dydx=0y = \frac{\mathrm{d}y}{\mathrm{d}x} = 0

解答