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CIE 9231 2025 Nov Paper 22 Q8

A Level / CIE / FP2

CIE 9231 2025 Nov Paper 22 Paper · Question 8

题目

Problem

(a) Find the values of kk for which the system of equations

xy+2kz=1,kx+y+2z=2,2xy+z=3,\begin{aligned} x - y + 2kz &= 1,\\ kx + y + 2z &= 2,\\ 2x - y + z &= 3, \end{aligned}

does not have a unique solution.

[3]

(b) Given that k=12k = -\frac{1}{2}, show that the system of equations in part (a) is inconsistent. Interpret this situation geometrically.

[3]

(c) Given instead that k=1k = -1, show that the system of equations in part (a) is also inconsistent. Interpret this situation geometrically.

[4]

The matrix A\mathbf{A} is given by

A=(112112211).\mathbf{A} = \begin{pmatrix} 1 & -1 & -2\\ -1 & 1 & 2\\ 2 & -1 & 1 \end{pmatrix}.

(d) Use the characteristic equation of A\mathbf{A} to show that A4=pA2+qA\mathbf{A}^4 = p\mathbf{A}^2 + q\mathbf{A} where pp and qq are integers to be determined.

[5]
题目中文翻译

(a) 求 kk 的值,使得方程组

xy+2kz=1,kx+y+2z=2,2xy+z=3\begin{aligned} x - y + 2kz &= 1,\\ kx + y + 2z &= 2,\\ 2x - y + z &= 3 \end{aligned}

没有唯一解。

(b) 已知 k=12k = -\frac{1}{2},证明 (a) 中的方程组不相容。用几何方式解释这种情况。

(c) 改为已知 k=1k = -1,证明 (a) 中的方程组同样不相容。用几何方式解释这种情况。

矩阵 A\mathbf{A} 定义为

A=(112112211).\mathbf{A} = \begin{pmatrix} 1 & -1 & -2\\ -1 & 1 & 2\\ 2 & -1 & 1 \end{pmatrix}.

(d) 使用 A\mathbf{A} 的特征方程证明 A4=pA2+qA\mathbf{A}^4 = p\mathbf{A}^2 + q\mathbf{A},其中 ppqq 是需要确定的整数。

解答