题目
Problem
The integral In is defined by
In=∫01(1+x2)ndx.
(a) By considering dxd(x(1+x2)n), or otherwise, show that
(2n+1)In=2n+2nIn−1.
[5]
(b) Find the exact value of I−2.
[4]
题目中文翻译
积分 In 定义为
In=∫01(1+x2)ndx.
(a) 通过考虑 dxd(x(1+x2)n),或用其他方法,证明
(2n+1)In=2n+2nIn−1.
(b) 求 I−2 的精确值。
解答