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CIE 9231 2022 June Paper 42 Q2

A Level / CIE / FS

CIE 9231 2022 June Paper 42 Paper · Question 2

题目

Problem

The probability generating function, GY(t)G_Y(t), of the random variable YY is given by

GY(t)=0.04+0.2t+0.37t2+0.3t3+0.09t4.G_Y(t) = 0.04 + 0.2t + 0.37t^2 + 0.3t^3 + 0.09t^4.

(a) Find Var(Y)\operatorname{Var}(Y).

[4]

The random variable YY is the sum of two independent observations of the random variable XX.

(b) Find the probability generating function of XX, giving your answer as a polynomial in tt.

[3]
题目中文翻译

随机变量 YY 的概率母函数 GY(t)G_Y(t)

GY(t)=0.04+0.2t+0.37t2+0.3t3+0.09t4.G_Y(t) = 0.04 + 0.2t + 0.37t^2 + 0.3t^3 + 0.09t^4.

(a) 求 Var(Y)\operatorname{Var}(Y)

随机变量 YY 是随机变量 XX 的两个独立观测值之和。

(b) 求 XX 的概率母函数,并将答案表示为 tt 的多项式。

解答