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CIE 9231 2022 June Paper 43 Q4

A Level / CIE / FS

CIE 9231 2022 June Paper 43 Paper · Question 4

题目

Problem

The continuous random variable XX has probability density function f given by

f(x)={38(1+1x2),1x3,0,otherwise.f(x) = \begin{cases} \dfrac{3}{8}\bigg(1 + \dfrac{1}{x^2}\bigg), & 1 \leq x \leq 3,\\ 0, & \text{otherwise.} \end{cases}

(a) Find E(X)\mathrm{E}(\sqrt{X}).

[3]

The random variable YY is given by Y=X2Y = X^2.

(b) Find the probability density function of YY.

[4]

(c) Find the 40th percentile of YY.

[3]
题目中文翻译

连续随机变量 XX 的概率密度函数 f 定义如下:

f(x)={38(1+1x2),1x3,0,otherwise.f(x) = \begin{cases} \dfrac{3}{8}\bigg(1 + \dfrac{1}{x^2}\bigg), & 1 \leq x \leq 3,\\ 0, & \text{otherwise.} \end{cases}

(a) 求 E(X)\mathrm{E}(\sqrt{X})

随机变量 YY 定义为 Y=X2Y = X^2

(b) 求 YY 的概率密度函数。

(c) 求 YY 的第 40 百分位数。

解答