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CIE 9231 2023 June Paper 43 Q1

A Level / CIE / FS

CIE 9231 2023 June Paper 43 Paper · Question 1

题目

Problem

The continuous random variable XX has probability density function ff given by

f(x)={16(x13x23),1x27,0,otherwise.f(x) = \begin{cases} \dfrac{1}{6}\big(x^{-\frac{1}{3}} - x^{-\frac{2}{3}}\big), & 1 \leq x \leq 27, \\ 0, & \text{otherwise.} \end{cases}

(a) Find the cumulative distribution function of XX.

[3]

The random variable YY is defined by Y=X13Y = X^{\frac{1}{3}}.

(b) Find the probability density function of YY.

[3]

(c) Find the exact value of the median of YY.

[2]
题目中文翻译

连续随机变量 XX 的概率密度函数 ff

f(x)={16(x13x23),1x27,0,otherwise.f(x) = \begin{cases} \dfrac{1}{6}\big(x^{-\frac{1}{3}} - x^{-\frac{2}{3}}\big), & 1 \leq x \leq 27, \\ 0, & \text{otherwise.} \end{cases}

(a) 求 XX 的累积分布函数。

随机变量 YY 定义为 Y=X13Y = X^{\frac{1}{3}}

(b) 求 YY 的概率密度函数。

(c) 求 YY 的中位数的精确值。

解答