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CIE 9231 2025 June Paper 42 Q4

A Level / CIE / FS

CIE 9231 2025 June Paper 42 Paper · Question 4

题目

Problem

A researcher is interested in whether there is a difference between two schools in students’ aptitude for English. She randomly chooses 10 students from school X and 8 students of a similar age from school Y to take a written English test. The scores for the students from school X (xx) and school Y (yy) are summarised as follows.

x=612x2=40104y=444y2=27460\sum x = 612 \qquad \sum x^2 = 40\,104 \qquad \sum y = 444 \qquad \sum y^2 = 27\,460

You should assume that the two distributions are normal and have the same population variance.

(a) Find a 95% confidence interval for the difference in the mean scores for students from school X and students from school Y in the written English test.

[6]

(b) Use the confidence interval you found in part (a) to explain why there is insufficient evidence at a 5% significance level to suggest that the English scores of students from school X and students from school Y are different.

[1]
题目中文翻译

一位研究人员想研究两所学校学生的英语能力是否存在差异。她从学校 X 随机选取 10 名学生,并从学校 Y 随机选取 8 名年龄相近的学生,让他们参加一场英语笔试。学校 X 学生的分数(xx)和学校 Y 学生的分数(yy)概括如下。

x=612x2=40104y=444y2=27460\sum x = 612 \qquad \sum x^2 = 40\,104 \qquad \sum y = 444 \qquad \sum y^2 = 27\,460

你应假设两个分布均为正态分布,且具有相同的总体方差。

(a) 求学校 X 学生与学校 Y 学生在英语笔试中总体平均分之差的 95% 置信区间。

(b) 使用你在 part (a) 中求得的置信区间,解释为什么在 5% 显著性水平下,没有足够证据表明学校 X 和学校 Y 学生的英语分数不同。

解答