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CIE 9231 2025 June Paper 43 Q3

A Level / CIE / FS

CIE 9231 2025 June Paper 43 Paper · Question 3

题目

Problem

A continuous random variable XX has probability density function ff given by

f(x)={kx,0x<1,k(8x),1x8,0,otherwise,f(x) = \begin{cases} kx, & 0 \leq x < 1, \\ k(8 - x), & 1 \leq x \leq 8, \\ 0, & \text{otherwise,} \end{cases}

where kk is a constant.

(a) Show that k=125k = \frac{1}{25}.

[2]

(b) Find the median value of XX.

[3]

The random variable YY is defined by Y=X3Y = \sqrt[3]{X}.

(c) Find the probability density function of YY.

[5]
题目中文翻译

连续随机变量 XX 的概率密度函数 ff 如下:

f(x)={kx,0x<1,k(8x),1x8,0,其他情况,f(x) = \begin{cases} kx, & 0 \leq x < 1, \\ k(8 - x), & 1 \leq x \leq 8, \\ 0, & \text{其他情况,} \end{cases}

其中 kk 是常数。

(a) 证明 k=125k = \frac{1}{25}

(b) 求 XX 的中位数。

随机变量 YY 定义为 Y=X3Y = \sqrt[3]{X}

(c) 求 YY 的概率密度函数。

解答