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CIE 9231 2025 June Paper 44 Q6

A Level / CIE / FS

CIE 9231 2025 June Paper 44 Paper · Question 6

题目

Problem

Lina and Mona are two statisticians who also write songs. The ‘time’ of a song is the number of minutes for which it lasts. For a random sample of 10 of her songs, Lina calculates a 95% confidence interval for the population mean time, μ\mu minutes. This confidence interval is 2.95μ3.132.95 \leq \mu \leq 3.13. The times, xx minutes, of Lina’s songs are normally distributed.

(a) Find the values of x\sum x and x2\sum x^2 for the 10 songs in Lina’s sample.

[5]

Mona’s songs have times, yy minutes, that are normally distributed. The times for a random sample of 8 of Mona’s songs are summarised as follows.

y=24.8y2=76.98\sum y = 24.8 \qquad \sum y^2 = 76.98

Mona claims that the population mean time of her songs is greater than the population mean time of Lina’s songs.

(b) Assuming that the two distributions have the same population variance, test at the 5% significance level whether there is evidence to support Mona’s claim.

[8]
题目中文翻译

Lina 和 Mona 是两位统计学家,她们也写歌。一首歌的“时长”是指这首歌持续的分钟数。Lina 从她的歌曲中随机抽取 10 首,计算总体平均时长 μ\mu 分钟的 95% 置信区间。该置信区间为 2.95μ3.132.95 \leq \mu \leq 3.13。Lina 歌曲的时长 xx 分钟服从正态分布。

(a) 求 Lina 样本中这 10 首歌的 x\sum xx2\sum x^2

Mona 歌曲的时长 yy 分钟服从正态分布。Mona 的 8 首歌曲组成的随机样本时长汇总如下。

y=24.8y2=76.98\sum y = 24.8 \qquad \sum y^2 = 76.98

Mona 声称她歌曲的总体平均时长大于 Lina 歌曲的总体平均时长。

(b) 假设两个分布具有相同的总体方差,在 5% 显著性水平下检验是否有证据支持 Mona 的说法。

解答