Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9231 2023 Nov Paper 42 Q3

A Level / CIE / FS

CIE 9231 2023 Nov Paper 42 Paper · Question 3

题目

Problem

Toby has a bag which contains 6 red marbles and 3 green marbles. He randomly chooses 3 marbles from the bag, without replacement. The random variable XX is the number of red marbles that Toby obtains.

(a) Find the probability generating function of XX.

[3]

Ling also has a bag which contains 6 red marbles and 3 green marbles. He randomly chooses 2 marbles from his bag, without replacement. The random variable YY is the number of red marbles that Ling obtains. It is given that the probability generating function of YY is 112(1+6t+5t2)\frac{1}{12}(1+6t+5t^2).

The random variable ZZ is the total number of red marbles that Toby and Ling obtain.

(b) Find the probability generating function of ZZ, expressing your answer as a polynomial in tt.

[3]

(c) Use the probability generating function of ZZ to find Var(Z)\operatorname{Var}(Z).

[4]
题目中文翻译

Toby 有一个袋子,里面有 6 个红色弹珠和 3 个绿色弹珠。他从袋中随机取出 3 个弹珠,且不放回。随机变量 XX 表示 Toby 取到的红色弹珠个数。

(a) 求 XX 的概率生成函数。

Ling 也有一个袋子,里面有 6 个红色弹珠和 3 个绿色弹珠。他从袋中随机取出 2 个弹珠,且不放回。随机变量 YY 表示 Ling 取到的红色弹珠个数。已知 YY 的概率生成函数为 112(1+6t+5t2)\frac{1}{12}(1+6t+5t^2)

随机变量 ZZ 表示 Toby 和 Ling 取到的红色弹珠总数。

(b) 求 ZZ 的概率生成函数,并将答案表示为关于 tt 的多项式。

(c) 使用 ZZ 的概率生成函数求 Var(Z)\operatorname{Var}(Z)

解答