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CIE 9709 2024 March Paper 12 Q5

A Level / CIE / P1

CIE 9709 2024 March Paper 12 Paper · Question 5

题目

Problem

A curve has the equation

y=32x25.y = \frac{3}{2x^2 - 5}.

Find the equation of the normal to the curve at the point (2,1)(2, 1), giving your answer in the form ax+by+c=0ax + by + c = 0, where aa, bb and cc are integers.

[6]
题目中文翻译

一条曲线的方程为

y=32x25y = \frac{3}{2x^2 - 5}

求该曲线在点 (2,1)(2, 1) 处的法线方程,并将答案写成 ax+by+c=0ax + by + c = 0 的形式,其中 aabbcc 是整数。

[6]

解答