Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9709 2025 March Paper 12 Q10

A Level / CIE / P1

CIE 9709 2025 March Paper 12 Paper · Question 10

题目

Problem

The diagram shows the curve with equation

y=4(3x+4)122x6y = 4(3x + 4)^{\frac{1}{2}} - 2x - 6

for values of xx such that 0x70 \leq x \leq 7. The tangent to the curve at the point P(7,0)P(7, 0) meets the yy-axis at the point QQ. Region AA is bounded by the curve and the two axes. Region BB is bounded by the curve, the line segment PQPQ and the yy-axis.

(a) Find the area of region AA.

[4]

(b) Find the area of region BB.

[5]
题目中文翻译

图中显示了方程为

y=4(3x+4)122x6y = 4(3x + 4)^{\frac{1}{2}} - 2x - 6

的曲线,其中 0x70 \leq x \leq 7。曲线在点 P(7,0)P(7, 0) 处的切线与 yy 轴相交于点 QQ。区域 AA 由曲线和两条坐标轴围成。区域 BB 由曲线、线段 PQPQyy 轴围成。

(a) 求区域 AA 的面积。

[4]

(b) 求区域 BB 的面积。

[5]

解答