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CIE 9709 2023 June Paper 12 Q11

A Level / CIE / P1

CIE 9709 2023 June Paper 12 Paper · Question 11

题目

Problem

The equation of a curve is

y=k4x+1x+5,y = k\sqrt{4x + 1} - x + 5,

where kk is a positive constant.

(a) Find dydx\frac{\mathrm{d}y}{\mathrm{d}x}.

[2]

(b) Find the xx-coordinate of the stationary point in terms of kk.

[2]

(c) Given that k=10.5k = 10.5, find the equation of the normal to the curve at the point where the tangent to the curve makes an angle of tan1(2)\tan^{-1}(2) with the positive xx-axis.

[4]
题目中文翻译

一条曲线的方程为

y=k4x+1x+5,y = k\sqrt{4x + 1} - x + 5,

其中 kk 为正常数。

(a) 求 dydx\frac{\mathrm{d}y}{\mathrm{d}x}

[2]

(b) 用 kk 表示驻点的 xx 坐标。

[2]

(c) 已知 k=10.5k = 10.5,在曲线上切线与正 xx 轴成 tan1(2)\tan^{-1}(2) 角的点处,求曲线的法线方程。

[4]

解答