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CIE 9709 2023 June Paper 12 Q9

A Level / CIE / P1

CIE 9709 2023 June Paper 12 Paper · Question 9

题目

Problem

The second term of a geometric progression is 1616 and the sum to infinity is 100100.

(a) Find the two possible values of the first term.

[4]

(b) Show that the nnth term of one of the two possible geometric progressions is equal to 4n24^{n - 2} multiplied by the nnth term of the other geometric progression.

[4]
题目中文翻译

一个等比数列的第二项为 1616,无穷和为 100100

(a) 求首项的两个可能值。

[4]

(b) 证明其中一个可能的等比数列的第 nn 项,等于另一个等比数列的第 nn 项乘以 4n24^{n - 2}

[4]

解答