题目

Problem

(a) Show that the equation $\frac{7\tan\theta}{\cos\theta} + 12 = 0$ can be expressed as

$12\sin^2\theta - 7\sin\theta - 12 = 0.$

[3]

(b) Hence solve the equation $\frac{7\tan\theta}{\cos\theta} + 12 = 0$ for $0^\circ \leq \theta \leq 360^\circ$ .

[3]

题目中文翻译

(a) 证明方程 $\frac{7\tan\theta}{\cos\theta} + 12 = 0$ 可以表示为

$12\sin^2\theta - 7\sin\theta - 12 = 0.$

[3]

(b) Hence 求解方程 $\frac{7\tan\theta}{\cos\theta} + 12 = 0$ ，其中 $0^\circ \leq \theta \leq 360^\circ$ 。

[3]

CIE 9709 2024 June Paper 12 Q3