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CIE 9709 2024 June Paper 12 Q4

A Level / CIE / P1

CIE 9709 2024 June Paper 12 Paper · Question 4

题目

Problem

The function ff is defined as follows:

f(x)=x1for x>1.f(x) = \sqrt{x} - 1 \quad \text{for } x > 1.

(a) Find an expression for f1(x)f^{-1}(x).

[1]

The diagram shows the graph of y=g(x)y = g(x) where g(x)=1x2+2g(x) = \frac{1}{x^2 + 2} for xRx \in \mathbb{R}.

(b) State the range of gg and explain whether g1g^{-1} exists.

[2]

The function hh is defined by h(x)=1x2+2h(x) = \frac{1}{x^2 + 2} for x0x \geq 0.

(c) Solve the equation hf(x)=f(2516)hf(x) = f\big(\frac{25}{16}\big). Give your answer in the form a+bca + b\sqrt{c}, where aa, bb and cc are integers.

[4]
题目中文翻译

函数 ff 定义如下:

f(x)=x1for x>1.f(x) = \sqrt{x} - 1 \quad \text{for } x > 1.

(a) 求 f1(x)f^{-1}(x) 的表达式。

[1]

图中显示 y=g(x)y = g(x) 的图像,其中 g(x)=1x2+2g(x) = \frac{1}{x^2 + 2}xRx \in \mathbb{R}

(b) 写出 gg 的值域,并说明 g1g^{-1} 是否存在。

[2]

函数 hh 定义为 h(x)=1x2+2h(x) = \frac{1}{x^2 + 2},其中 x0x \geq 0

(c) 解方程 hf(x)=f(2516)hf(x) = f\big(\frac{25}{16}\big)。答案写成 a+bca + b\sqrt{c} 的形式,其中 aabbcc 是整数。

[4]

解答