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CIE 9709 2024 June Paper 13 Q4

A Level / CIE / P1

CIE 9709 2024 June Paper 13 Paper · Question 4

题目

Problem

(a) Show that the equation cosθ(7tanθ5cosθ)=1\cos\theta(7\tan\theta - 5\cos\theta) = 1 can be written in the form asin2θ+bsinθ+c=0a\sin^2\theta + b\sin\theta + c = 0, where aa, bb and cc are integers to be found.

[3]

(b) Hence solve the equation cos2x(7tan2x5cos2x)=1\cos 2x(7\tan 2x - 5\cos 2x) = 1 for 0<x<1800^\circ < x < 180^\circ.

[3]
题目中文翻译

(a) 证明方程 cosθ(7tanθ5cosθ)=1\cos\theta(7\tan\theta - 5\cos\theta) = 1 可以写成 asin2θ+bsinθ+c=0a\sin^2\theta + b\sin\theta + c = 0 的形式,其中 aabbcc 是需要求出的整数。

[3]

(b) Hence 求解方程 cos2x(7tan2x5cos2x)=1\cos 2x(7\tan 2x - 5\cos 2x) = 1,其中 0<x<1800^\circ < x < 180^\circ

[3]

解答