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CIE 9709 2025 June Paper 11 Q2

A Level / CIE / P1

CIE 9709 2025 June Paper 11 Paper · Question 2

题目

Problem

The equation of a curve is such that dydx=4(2x5)39x12\frac{dy}{dx} = 4(2x - 5)^3 - 9x^{\frac{1}{2}}. The curve passes through the point A(4,112)A\left(4, -\frac{11}{2}\right).

(a) Find the gradient of the normal to the curve at the point AA.

[2]

(b) Find the equation of the curve.

[4]
题目中文翻译

一条曲线满足 dydx=4(2x5)39x12\frac{dy}{dx} = 4(2x - 5)^3 - 9x^{\frac{1}{2}}。该曲线经过点 A(4,112)A\left(4, -\frac{11}{2}\right)

(a) 求曲线在点 AA 处的法线斜率。

[2]

(b) 求曲线方程。

[4]

解答