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CIE 9709 2025 June Paper 12 Q5

A Level / CIE / P1

CIE 9709 2025 June Paper 12 Paper · Question 5

题目

Problem

The equation of a curve is y=4cos2x+3y = 4\cos 2x + 3 for 0x2π0 \leq x \leq 2\pi.

(a) State the greatest and least possible values of yy.

[2]

(b) Sketch the curve.

[2]

(c) Hence determine the number of solutions of the equation 4cos2x+3=2x14\cos 2x + 3 = 2x - 1 for 0x2π0 \leq x \leq 2\pi.

[1]
题目中文翻译

一条曲线的方程为 y=4cos2x+3y = 4\cos 2x + 3,其中 0x2π0 \leq x \leq 2\pi

(a) 写出 yy 的最大可能值和最小可能值。

[2]

(b) 画出该曲线的草图。

[2]

(c) 由此判断方程 4cos2x+3=2x14\cos 2x + 3 = 2x - 10x2π0 \leq x \leq 2\pi 范围内的解的个数。

[1]

解答