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CIE 9709 2025 June Paper 13 Q10

A Level / CIE / P1

CIE 9709 2025 June Paper 13 Paper · Question 10

题目

Problem

A curve CC has equation y=92x5+2x5y = \frac{9}{2x - 5} + 2x - 5.

(a) Find the coordinates of the two stationary points.

[4]

(b) Find d2ydx2\frac{d^2y}{dx^2} and hence determine the nature of each stationary point.

[3]

(c) The curve CC is transformed to the curve C1C_1 using a translation of (37)\begin{pmatrix}-3\\7\end{pmatrix} followed by reflection in the xx-axis.

(i) State the coordinates of the maximum point of C1C_1.

[1]

(ii) Find the equation of C1C_1 in the form y=abx+c+dx+ey = \frac{a}{bx + c} + dx + e, where aa, bb, cc, dd and ee are integers.

[3]
题目中文翻译

一条曲线 CC 的方程为 y=92x5+2x5y = \frac{9}{2x - 5} + 2x - 5

(a) 求两个驻点的坐标。

[4]

(b) 求 d2ydx2\frac{d^2y}{dx^2},并由此判断每个驻点的性质。

[3]

(c) 曲线 CC 通过平移 (37)\begin{pmatrix}-3\\7\end{pmatrix},再关于 xx 轴反射,变换为曲线 C1C_1

(i) 写出 C1C_1 的极大点坐标。

[1]

(ii) 求 C1C_1 的方程,写成 y=abx+c+dx+ey = \frac{a}{bx + c} + dx + e 的形式,其中 aabbccddee 为整数。

[3]

解答