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CIE 9709 2025 June Paper 13 Q2

A Level / CIE / P1

CIE 9709 2025 June Paper 13 Paper · Question 2

题目

Problem

The first two terms of a geometric progression are 4sin2θ4\sin^2\theta, 8sin3θ8\sin^3\theta, where θ\theta is an angle such that 0<θ<16π0 < \theta < \frac{1}{6}\pi.

Given that the sum to infinity of the progression is 12\frac{1}{2}, find the value of θ\theta. Give your answer in the form sin1k\sin^{-1} k, where kk is a rational number.

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题目中文翻译

一个等比数列的前两项为 4sin2θ4\sin^2\theta8sin3θ8\sin^3\theta,其中 θ\theta 是满足 0<θ<16π0 < \theta < \frac{1}{6}\pi 的角。

已知该数列的无穷和为 12\frac{1}{2},求 θ\theta 的值。答案写成 sin1k\sin^{-1} k 的形式,其中 kk 是有理数。

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解答