Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9709 2025 June Paper 13 Q3

A Level / CIE / P1

CIE 9709 2025 June Paper 13 Paper · Question 3

题目

Problem

Given that 13(a(4x3)2+2)dx=12\int_1^3 \left(\frac{a}{(4x - 3)^2} + 2\right)\,dx = 12, find the value of the constant aa.

[4]
题目中文翻译

已知 13(a(4x3)2+2)dx=12\int_1^3 \left(\frac{a}{(4x - 3)^2} + 2\right)\,dx = 12,求常数 aa 的值。

[4]

解答