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CIE 9709 2025 June Paper 15 Q9

A Level / CIE / P1

CIE 9709 2025 June Paper 15 Paper · Question 9

题目

Problem

Functions ff and gg are defined as follows.

f(x)=cosxfor 0xπf(x)=\cos x\quad\text{for }0\leq x\leq\pi

g(x)=3cos(xπ)+2for πx2πg(x)=3\cos(x-\pi)+2\quad\text{for }\pi\leq x\leq2\pi

(a) Describe fully the transformations that have been combined to transform the graph of y=f(x)y=f(x) to the graph of y=g(x)y=g(x).

[4]

(b) On the given axes, sketch the graphs of y=f(x)y=f(x) and y=g(x)y=g(x).

[4]

(c) Find g1f(13π)g^{-1}f\left(\frac{1}{3}\pi\right).

[4]

(d) Explain why the composite function fgfg cannot be formed.

[1]
题目中文翻译

函数 ffgg 定义如下。

f(x)=cosx其中 0xπf(x)=\cos x\quad\text{其中 }0\leq x\leq\pi

g(x)=3cos(xπ)+2其中 πx2πg(x)=3\cos(x-\pi)+2\quad\text{其中 }\pi\leq x\leq2\pi

(a) 完整描述将 y=f(x)y=f(x) 的图像变换为 y=g(x)y=g(x) 的组合变换。

(b) 在给定坐标轴上画出 y=f(x)y=f(x)y=g(x)y=g(x) 的图像草图。

(c) 求 g1f(13π)g^{-1}f\left(\frac{1}{3}\pi\right)

(d) 解释为什么复合函数 fgfg 不能形成。

解答