Skip to content
CalcGospel 國際數學圖譜
返回

CIE 9709 2024 November Paper 11 Q8

A Level / CIE / P1

CIE 9709 2024 Nov Paper 11 Paper · Question 8

题目

Problem

(a) It is given that β\beta is an angle between 9090^\circ and 180180^\circ such that sinβ=a\sin\beta=a.

Express tan2β3sinβcosβ\tan^2\beta-3\sin\beta\cos\beta in terms of aa.

[3]

(b) Solve the equation sin2θ+2cos2θ=4sinθ+3\sin^2\theta+2\cos^2\theta=4\sin\theta+3 for 0<θ<3600^\circ<\theta<360^\circ.

[5]
题目中文翻译

(a) 已知 β\beta 是一个介于 9090^\circ180180^\circ 之间的角,且 sinβ=a\sin\beta=a

aa 表示 tan2β3sinβcosβ\tan^2\beta-3\sin\beta\cos\beta

(b) 解方程 sin2θ+2cos2θ=4sinθ+3\sin^2\theta+2\cos^2\theta=4\sin\theta+3,其中 0<θ<3600^\circ<\theta<360^\circ

解答