题目 Problem Find the exact solution of the equation cos16π+tan2x+32=0\cos\frac{1}{6}\pi + \tan 2x + \frac{\sqrt{3}}{2} = 0cos61π+tan2x+23=0 for −14π<x<14π-\frac{1}{4}\pi < x < \frac{1}{4}\pi−41π<x<41π. [2] 题目中文翻译 求方程 cos16π+tan2x+32=0\cos\frac{1}{6}\pi + \tan 2x + \frac{\sqrt{3}}{2} = 0cos61π+tan2x+23=0 在 −14π<x<14π-\frac{1}{4}\pi < x < \frac{1}{4}\pi−41π<x<41π 范围内的精确解。 解答
