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CIE 9709 2025 Nov Paper 12 Q4

A Level / CIE / P1

CIE 9709 2025 Nov Paper 12 Paper · Question 4

题目

Problem

The equation of a curve is such that dydx=kx3+2x2\frac{dy}{dx}=kx^3+\frac{2}{x^2}, where kk is a constant. The curve passes through the point S(2,20)S(2,20) and the gradient of the curve at SS is 652\frac{65}{2}.

(a) Find the value of kk.

[1]

(b) The coordinates of a point TT on the curve are (1,t)(1,t).

Find the value of tt.

[5]
题目中文翻译

一条曲线满足 dydx=kx3+2x2\frac{dy}{dx}=kx^3+\frac{2}{x^2},其中 kk 是常数。该曲线经过点 S(2,20)S(2,20),并且曲线在 SS 处的梯度为 652\frac{65}{2}

(a) 求 kk 的值。

(b) 曲线上一点 TT 的坐标为 (1,t)(1,t)

tt 的值。

解答