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CIE 9709 2025 Nov Paper 13 Q11

A Level / CIE / P1

CIE 9709 2025 Nov Paper 13 Paper · Question 11

题目

Problem

The equation of a curve is y=83x86x1y=\frac{8}{3x-8}-\frac{6}{x-1}.

(a) Find the coordinates of the point at which the tangent to the curve at the point (3,5)(3,5) intersects the line y=8xy=-8x.

[6]

(b) (i) Find the xx-coordinates of each of the stationary points of the curve.

[3]

(ii) Find d2ydx2\frac{\mathrm{d}^2y}{\mathrm{d}x^2} and hence determine the nature of each of the stationary points.

[4]
题目中文翻译

一条曲线的方程为 y=83x86x1y=\frac{8}{3x-8}-\frac{6}{x-1}

(a) 求曲线在点 (3,5)(3,5) 处的切线与直线 y=8xy=-8x 的交点坐标。

(b) (i) 求曲线每个驻点的 xx 坐标。

(ii) 求 d2ydx2\frac{\mathrm{d}^2y}{\mathrm{d}x^2},并由此判断每个驻点的性质。

解答