Skip to content
CalcGospel 國際數學圖譜
返回

IAL 2022 Jan FP1 Q9

A Level / Edexcel / FP1

IAL 2022 Jan Paper · Question 9

题目

Problem

(a) Prove by induction that, for nZ+n \in \mathbb{Z}^+

r=1nr3=14n2(n+1)2\sum_{r=1}^{n} r^3 = \frac{1}{4}n^2(n + 1)^2

(5)

(b) Using the standard summation formulae, show that

r=1nr(r+1)(r1)=14n(n+A)(n+B)(n+C)\sum_{r=1}^{n} r(r + 1)(r - 1) = \frac{1}{4}n(n + A)(n + B)(n + C)

where AA, BB and CC are constants to be determined.

(4)

(c) Determine the value of nn for which

3r=1nr(r+1)(r1)=17r=n2nr23\sum_{r=1}^{n} r(r + 1)(r - 1) = 17\sum_{r=n}^{2n} r^2

(5)
题目中文翻译

(a) 用数学归纳法证明:对于 nZ+n \in \mathbb{Z}^+r=1nr3=14n2(n+1)2\sum_{r=1}^{n} r^3 = \frac{1}{4}n^2(n + 1)^2

(b) 使用标准求和公式证明 r=1nr(r+1)(r1)=14n(n+A)(n+B)(n+C)\sum_{r=1}^{n} r(r + 1)(r - 1) = \frac{1}{4}n(n + A)(n + B)(n + C) 其中 AABBCC 为待确定的常数。

(c) 确定使下式成立的 nn3r=1nr(r+1)(r1)=17r=n2nr23\sum_{r=1}^{n} r(r + 1)(r - 1) = 17\sum_{r=n}^{2n} r^2

解答