题目 Problem 9. Prove, by induction, that for n∈Zn \in \mathbb{Z}n∈Z, n≥2n \geq 2n≥2 4n+6n−104^n + 6^n - 104n+6n−10 is divisible by 181818 (5) 题目中文翻译 用数学归纳法证明，对于 n∈Zn \in \mathbb{Z}n∈Z，n≥2n \geq 2n≥2 4n+6n−104^n + 6^n - 104n+6n−10 能被 181818 整除。 解答
