题目
Problem
In this question use the standard results for summations.
(a) Show that for all positive integers n
∑r=1n(12r2+2r−3)=An3+Bn2
where A and B are integers to be determined.
(4)
(b) Hence determine the value of n for which
∑r=12nr3−∑r=1n(12r2+2r−3)=270
(4)
题目中文翻译
本题使用标准求和公式。
(a) 证明对所有正整数 n,均有
∑r=1n(12r2+2r−3)=An3+Bn2
其中 A 和 B 为待求的整数。
(b) 由此确定满足以下等式的 n 值:
∑r=12nr3−∑r=1n(12r2+2r−3)=270
解答