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IAL 2026 Jan A FP1 Q5

A Level / Edexcel / FP1

IAL 2026 Jan A Paper · Question 5

Question

[!problem]

The quadratic equation

x22x+3=0x^2 - 2x + 3 = 0

has roots α\alpha and β\beta.

Without solving the equation,

(a) (i) write down the value of (α+β)(\alpha + \beta) and the value of αβ\alpha\beta.

(ii) show that α2+β2=2\alpha^2 + \beta^2 = -2.

(iii) find the value of α4+β4\alpha^4 + \beta^4.

(5)

(b) (i) show that α3+β3=(α+β)33αβ(α+β)\alpha^3 + \beta^3 = (\alpha + \beta)^3 - 3\alpha\beta(\alpha + \beta).

(ii) find a quadratic equation which has roots

(α3β3) and (β3α3)(\alpha^3 - \beta^3) \text{ and } (\beta^3 - \alpha^3)

giving your answer in the form px2+qx+r=0px^2 + qx + r = 0 where pp, qq and rr are integers.

(6)

中文翻译

二次方程

x22x+3=0x^2 - 2x + 3 = 0

有根 α\alphaβ\beta

不解方程,

(a) (i) 写出 (α+β)(\alpha + \beta) 的值和 αβ\alpha\beta 的值。

(ii) 证明 α2+β2=2\alpha^2 + \beta^2 = -2

(iii) 求 α4+β4\alpha^4 + \beta^4 的值。

(5)

(b) (i) 证明 α3+β3=(α+β)33αβ(α+β)\alpha^3 + \beta^3 = (\alpha + \beta)^3 - 3\alpha\beta(\alpha + \beta)

(ii) 求一个二次方程,使其根为

(α3β3) 和 (β3α3)(\alpha^3 - \beta^3) \text{ 和 } (\beta^3 - \alpha^3)

将答案写成 px2+qx+r=0px^2 + qx + r = 0 的形式,其中 ppqqrr 是整数。

(6)