题目
Problem
Figure 4 shows a sketch of part of the curve C with equation y=f(x), where
f(x)=(3x−2)2(x−4).
Figure 4
(a) Deduce the values of x for which f(x)>0.
(1)
(b) Expand f(x) to the form
ax3+bx2+cx+d
where a, b, c and d are integers to be found.
(3)
The line l, also shown in Figure 4, passes through the y intercept of C and is parallel to the x-axis.
The line l cuts C again at points P and Q, also shown in Figure 4.
(c) Using algebra and showing your working, find the length of line PQ. Write your answer in the form k3, where k is a constant to be found.
(Solutions relying entirely on calculator technology are not acceptable.)
(5)
解答
(a)
解法一
思路
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(3x−2)2 永远非负,且在 x=32 时为 0。函数符号主要由 (x−4) 决定,所以只有 x>4 时为正。
答题过程
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Since (3x−2)2≥0, the sign of f(x) is determined by x−4 except at the repeated root x=32.
Therefore
f(x)>0forx>4.
(b)
解法一
思路
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先展开平方,再乘以 (x−4)。
答题过程
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f(x)====(3x−2)2(x−4)(9x2−12x+4)(x−4)9x3−36x2−12x2+48x+4x−169x3−48x2+52x−16.
(c)
解法一
思路
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直线 l 经过 C 的 y 轴截距,所以先找 f(0)。因为 l 是水平线,P,Q 的 y 坐标相同,长度 PQ 就是两个对应 x 坐标之差。
答题过程
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The y-intercept of C is
f(0)===(3(0)−2)2(0−4)4(−4)−16.
So line l has equation
y=−16.
Find where C meets this line:
9x3−48x2+52x−16=9x3−48x2+52x=x(9x2−48x+52)=−1600.
The non-zero intersections satisfy
9x2−48x+52=0.
Using the quadratic formula,
x====1848±482−4(9)(52)1848±4321848±12338±23.
Therefore
PQ==38+23−38−23343.