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IAL 2023 Jan Q3

A Level / Edexcel / P1

IAL 2023 Jan Paper · Question 3

题目

Problem

Find

4x5+32x2dx\begin{align*} \int \frac{4x^5+3}{2x^2}\,\mathrm{d}x \end{align*}

giving your answer in simplest form.

(5)
题目中文翻译

4x5+32x2dx,\begin{align*} \int \frac{4x^5+3}{2x^2}\,\mathrm{d}x, \end{align*}

并将答案写成最简形式。

解答

解法一

思路

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分母是单项式,所以先把分子每一项分别除以 2x22x^2。这样可以把分式改写成幂函数之和,再逐项积分。

答题过程

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First rewrite the integrand:

4x5+32x2=4x52x2+32x2=2x3+32x2.\begin{align*} \frac{4x^5+3}{2x^2} =&\,\frac{4x^5}{2x^2}+\frac3{2x^2}\\ =&\,2x^3+\frac32x^{-2}. \end{align*}

Therefore

4x5+32x2dx=(2x3+32x2)dx=12x432x1+c=12x432x+c.\begin{align*} \int \frac{4x^5+3}{2x^2}\,\mathrm{d}x =&\,\int \left(2x^3+\frac32x^{-2}\right)\,\mathrm{d}x\\ =&\,\frac12x^4-\frac32x^{-1}+c\\ =&\,\frac12x^4-\frac3{2x}+c. \end{align*}