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IAL 2023 May Q4

A Level / Edexcel / P1

IAL 2023 May Paper · Question 4

题目

Problem

In this question you must show all stages of your working.

(a) Write

y=5x2+x38x3\begin{align*} y=\frac{5x^2+\sqrt{x^3}}{\sqrt[3]{8x}} \end{align*}

in the form

y=Axp+Bxq\begin{align*} y=Ax^p+Bx^q \end{align*}

where AA, BB, pp and qq are constants to be found.

(4)

(b) Hence find dydx\dfrac{dy}{dx} giving each coefficient in simplest form.

(3)

解答

(a)

解法一

思路

展开

把根式全部改写成指数,再分别除以分母。这里 8x3=2x1/3\sqrt[3]{8x}=2x^{1/3}

答题过程

展开 y=5x2+x38x3=5x2+x322x13=5x22x13+x322x13=52x213+12x3213=52x53+12x76.\begin{align*} y =&\,\frac{5x^2+\sqrt{x^3}}{\sqrt[3]{8x}}\\ =&\,\frac{5x^2+x^{\frac32}}{2x^{\frac13}}\\ =&\,\frac{5x^2}{2x^{\frac13}} +\frac{x^{\frac32}}{2x^{\frac13}}\\ =&\,\frac52x^{2-\frac13} +\frac12x^{\frac32-\frac13}\\ =&\,\frac52x^{\frac53}+\frac12x^{\frac76}. \end{align*}

Therefore

A=52,p=53,B=12,q=76.\begin{align*} A=\frac52,\qquad p=\frac53,\qquad B=\frac12,\qquad q=\frac76. \end{align*}

(b)

解法一

思路

展开

直接对 (a) 的幂函数形式逐项求导。

答题过程

展开

From part (a),

y=52x53+12x76.\begin{align*} y=\frac52x^{\frac53}+\frac12x^{\frac76}. \end{align*}

Differentiate:

dydx=5253x23+1276x16=256x23+712x16.\begin{align*} \frac{dy}{dx} =&\,\frac52\cdot\frac53x^{\frac23} +\frac12\cdot\frac76x^{\frac16}\\ =&\,\frac{25}{6}x^{\frac23}+\frac{7}{12}x^{\frac16}. \end{align*}