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IAL 2023 Oct Q5

A Level / Edexcel / P2

IAL 2023 Oct Paper · Question 5

题目

Problem

In this question you must show all stages of your working. Solutions relying entirely on calculator technology are not acceptable.

(i) Solve 3a=703^a = 70, giving the answer to 3 decimal places.

(ii) Find the exact value of bb such that

4+3log3b=log3(5b)4 + 3\log_3 b = \log_3(5b)

(6)
题目中文翻译

本题必须展示所有解题步骤,不能完全依赖计算器技术。

(i) 解 3a=703^a = 70,答案保留3位小数。

(ii) 求满足 4+3log3b=log3(5b)4 + 3\log_3 b = \log_3(5b)bb 的精确值。

(6分)

解答

解法一

思路

(i) 对 3a=703^a = 70 两边取对数,利用换底公式求解。 (ii) 利用对数运算法则化简方程,转化为指数方程求解。

答题过程

(i) Solve 3a=703^a = 70:

\log 3^a =&\, \log 70 \\ a \log 3 =&\, \log 70 \\ a =&\, \frac{\log 70}{\log 3} = 3.867 \end{align*}$$ $$\boxed{a = 3.867}$$ **(ii)** Solve $4 + 3\log_3 b = \log_3(5b)$: $$\begin{align*} 4 + \log_3 b^3 =&\, \log_3(5b) \\ 4 =&\, \log_3(5b) - \log_3 b^3 \\ 4 =&\, \log_3 \frac{5b}{b^3} \\ 4 =&\, \log_3 \frac{5}{b^2} \end{align*}$$ Converting to index form: $$\begin{align*} 3^4 =&\, \frac{5}{b^2} \\ 81 =&\, \frac{5}{b^2} \\ b^2 =&\, \frac{5}{81} \\ b =&\, \frac{\sqrt{5}}{9} \end{align*}$$ (Taking the positive value since the argument of a logarithm must be positive.) $$\boxed{b = \frac{\sqrt{5}}{9}}$$