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IAL 2024 Jan Q2

A Level / Edexcel / P2

IAL 2024 Jan Paper · Question 2

题目

Problem

Find the coefficient of the term in x7x^7 in the binomial expansion of

(38+4x)12\left(\frac38+4x\right)^{12}
(3)

解答

解法一

思路

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(a+b)12\left(a+b\right)^{12} 中,含 x7x^7 的项一定来自 (4x)7(4x)^7,所以另一部分是 (38)5\left(\frac38\right)^5

答题过程

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The term in x7x^7 is

(127)(38)5(4x)7.\binom{12}{7} \left(\frac38\right)^5 (4x)^7.

So the coefficient of x7x^7 is

(127)(38)547=792(24332768)(16384)=96228.\begin{align*} \binom{12}{7} \left(\frac38\right)^5 4^7 =&\,792\left(\frac{243}{32768}\right)(16384)\\ =&\,96228. \end{align*}

Therefore, the coefficient is

96228.\begin{align*} 96228. \end{align*}