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IAL 2024 Oct Q11

A Level / Edexcel / P2

IAL 2024 Oct Paper · Question 11

题目

Problem

(i) Prove by counter example that the statement

“If nn is a prime number then 3n+23^n+2 is also a prime number.”

is false.

(2)

(ii) Use proof by exhaustion to prove that if mm is an integer that is not divisible by 33, then

m21m^2-1

is divisible by 33

(4)

解答

(i)

解法一

思路

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反例只需要找一个 prime nn,使 3n+23^n+2 不是 prime。选 n=5n=5 很方便。

答题过程

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Take

n=5.\begin{align*} n=5. \end{align*}

This is prime. But

35+2=243+2=245=5×49.\begin{align*} 3^5+2=&\,243+2\\ =&\,245\\ =&\,5\times49. \end{align*}

So 35+23^5+2 is not prime. Therefore, the statement is false.

(ii)

解法一

思路

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一个整数不被 33 整除,只可能形如 3k+13k+13k+23k+2。proof by exhaustion 就是把这两种情况都检查完。

答题过程

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If mm is not divisible by 33, then either

m=3k+1\begin{align*} m=3k+1 \end{align*}

or

m=3k+2,\begin{align*} m=3k+2, \end{align*}

where kk is an integer.

Case 1:

m=3k+1m21=(3k+1)21=9k2+6k+11=9k2+6k=3(3k2+2k).\begin{align*} m=&\,3k+1\\ m^2-1=&\,(3k+1)^2-1\\ =&\,9k^2+6k+1-1\\ =&\,9k^2+6k\\ =&\,3(3k^2+2k). \end{align*}

So m21m^2-1 is divisible by 33.

Case 2:

m=3k+2m21=(3k+2)21=9k2+12k+41=9k2+12k+3=3(3k2+4k+1).\begin{align*} m=&\,3k+2\\ m^2-1=&\,(3k+2)^2-1\\ =&\,9k^2+12k+4-1\\ =&\,9k^2+12k+3\\ =&\,3(3k^2+4k+1). \end{align*}

So m21m^2-1 is divisible by 33.

In all possible cases where mm is not divisible by 33, m21m^2-1 is divisible by 33.