Problem

Find the particular solution of the differential equation

$$\frac{dy}{dx}=\frac{4y^2}{\sqrt{4x+5}} \qquad x>-\frac{5}{4}$$

for which $y=\dfrac{1}{3}$ at $x=-\dfrac{1}{4}$ giving your answer in the form $y=\mathrm{f}(x)$