Skip to content
CalcGospel 國際數學圖譜
返回

IAL 2023 June S3 Q4

A Level / Edexcel / S3

IAL 2023 June Paper · Question 4

题目

Problem

It is suggested that the delay, in hours, of certain flights from a particular country may be modelled by the continuous random variable, T, with probability density function

f(t)={t25,0t<50,otherwisef(t)= \begin{cases} \frac{t}{25}, & 0 \le t < 5 \\ 0, & \text{otherwise} \end{cases}

(a) Show that for 0a40 \le a \le 4

P(aT<a+1)=125(2a+1)P(a \le T < a+1)=\frac{1}{25}(2a+1)

A random sample of 150 of these flights is taken. The delays are summarised in the table below.

Delay (t hours)Frequency
0t<10 \le t < 110
1t<21 \le t < 213
2t<32 \le t < 324
3t<43 \le t < 435
4t<54 \le t < 568

(b) Test, at the 5% significance level, whether the given probability density function is a suitable model for these delays. You should state your hypotheses, expected frequencies, test statistic and the critical value used.

(3)
(8)
(Total for Question 4 is 11 marks)
题目中文翻译

据推测,某国某些航班的延误时间(小时)可由连续随机变量 TT 建模,其概率密度函数为

f(t)={t25,0t<50,otherwisef(t)= \begin{cases} \frac{t}{25}, & 0 \le t < 5 \\ 0, & \text{otherwise} \end{cases}

(a) 证明当 0a40 \le a \le 4 时,

P(aT<a+1)=125(2a+1)P(a \le T < a+1)=\frac{1}{25}(2a+1)

随机抽取了 150 个此类航班,并将延误情况整理如下表。

延误时间(t 小时)频数
0t<10 \le t < 110
1t<21 \le t < 213
2t<32 \le t < 324
3t<43 \le t < 435
4t<54 \le t < 568

(b) 在 5% 显著性水平下,检验给定的概率密度函数是否适合作为这些延误时间的模型。 你应写出原假设、期望频数、检验统计量和所用临界值。

解答